<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0">
 <channel>
  <title>Shilcare</title>
  <link>http://shilcare.blogbus.com</link>
  <description><![CDATA[Welcome to my blog, enjoy Your stay.]]></description>
  <generator> by blogbus.com </generator>
  <lastBuildDate>Thu, 01 Jan 1970 07:00:00 +0700</lastBuildDate>
  <image>
									<url>http://public.blogbus.com/profile/0/7/6/5918670/avatar_5918670_96.jpg</url>
									<title>Shilcare</title>
									<link>http://shilcare.blogbus.com</link>
								</image>  <item>
   <title>全排列生成</title>
   <description><![CDATA[<p>全排列生成的办法很多，比如可以直接DFS遍历，像走迷宫一样，从起点开始，然后从这n个点选一<br />
<br />
个走，并打上标记，然后走下一点，走下一点前，看看那个点是不是被标记了，没标记的再走。下一<br />
<br />
点要是能走的都走过了，就退上一步换另一个点，走到不能走为止。<br />
<br />
单纯的...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060678.html&title=%E5%85%A8%E6%8E%92%E5%88%97%E7%94%9F%E6%88%90">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060678.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:22:00 +0800</pubDate>
  </item>
  <item>
   <title>POJ 1094 - Sorting It All Out</title>
   <description><![CDATA[<p><br />
Sorting It All OutTime Limit: 1000MS&nbsp;Memory Limit: 10000KTotal Submissions: 12428&nbsp;Accepted: 4057Description<br />
An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements ...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060639.html&title=POJ+1094+-+Sorting+It+All+Out">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060639.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:21:00 +0800</pubDate>
  </item>
  <item>
   <title>POJ 1915 - Knight Moves</title>
   <description><![CDATA[<p><br />
<br />
Knight Moves<br />
<br />
Time Limit: 1000MS<br />
&nbsp;<br />
Memory Limit: 30000K<br />
<br />
Total Submissions: 12076<br />
&nbsp;<br />
Accepted: 5287<br />
<br />
Description<br />
<br />
Background <br />
Mr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from one position...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060545.html&title=POJ+1915+-+Knight+Moves">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060545.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:19:00 +0800</pubDate>
  </item>
  <item>
   <title>a^n mod k 幂取模</title>
   <description><![CDATA[<p>密码学领域中经常会遇到一种运算，就是求一个数的幂对另一个数的模的运算 a^n mod k，也称为幂取模。<br />
<br />
对于搞过竞赛算法的人来说，powmod可能不会陌生，它是一个计算a^b mod m的函数，但abmod你可能不<br />
<br />
知道，它其实意思更简单，是计算a*b mod m的函数。powmod的出现...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060469.html&title=a%5En+mod+k+%E5%B9%82%E5%8F%96%E6%A8%A1">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060469.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:17:00 +0800</pubDate>
  </item>
  <item>
   <title>并查集及其应用举例</title>
   <description><![CDATA[<p>什么是并查集<br />并查集是一种树型的数据结构，用于处理一些不相交集合（Disjoint Sets）的合并及查询问题。<br />常常在使用中以森林来表示。进行快速规整。<br />并查集的主要操作<br /><br />合并两个不相交集合<br /><br />判断两个元素是否属于同一集合<br /><br />主要操作的解释<br />需要注意的是，一开始我们...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060382.html&title=%E5%B9%B6%E6%9F%A5%E9%9B%86%E5%8F%8A%E5%85%B6%E5%BA%94%E7%94%A8%E4%B8%BE%E4%BE%8B">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060382.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:14:00 +0800</pubDate>
  </item>
  <item>
   <title>树状数组介绍</title>
   <description><![CDATA[<p>一种好的数据结构能让我们的算法变得更快。树状数组(Binary Index Tree)就是这样一种数据结构。<br /><br />我们经常会遇到这样的问题：<br /><br />修改数组元素A[i]; <br />查询数组A某一区间元素的和;<br /><br />用原始的方法修改需要O(1), 查询要O(n)。而使用树状数组，修改和查询都可以在O(log n)...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76060319.html&title=%E6%A0%91%E7%8A%B6%E6%95%B0%E7%BB%84%E4%BB%8B%E7%BB%8D">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76060319.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:11:00 +0800</pubDate>
  </item>
  <item>
   <title>POJ 2299 - Ultra QuickSort </title>
   <description><![CDATA[<p>Ultra-QuickSort <br /><br />&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&amp;...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F76059802.html&title=POJ+2299+-+Ultra+QuickSort+">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/76059802.html</link>
   <author>shilcare</author>
   <pubDate>Fri, 01 Oct 2010 02:06:00 +0800</pubDate>
  </item>
  <item>
   <title>未知的以后</title>
   <description><![CDATA[<p>未知的以后<br /><br />蔡淳佳<br /><br />&nbsp;<br /><br />越过雾&nbsp; 越过风<br /><br />有过眼泪和感动<br /><br />一开始祝福什么<br /><br />只有未知的以后<br /><br />雨或晴&nbsp; 都匆匆<br /><br />只能学习着把握<br /><br />再美的春夏秋冬<br /><br />不能为谁而停留<br /><br />很想牵着你的手<br />...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F74318355.html&title=%E6%9C%AA%E7%9F%A5%E7%9A%84%E4%BB%A5%E5%90%8E">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/74318355.html</link>
   <author>shilcare</author>
   <pubDate>Sat, 04 Sep 2010 17:30:12 +0800</pubDate>
  </item>
  <item>
   <title>SPOJ 345 Mixtures</title>
   <description><![CDATA[<p>这道题是经典题目&ldquo;石子合并&rdquo;的变形。同样也是用动态规划来解。<br /><br />用dp[i, j]表示从第 i 堆开始的 j 堆混合物合并所释放的最少烟雾量，sum[i, k]表示从第 i 堆开始的 j 堆<br /><br />混合物合并后的颜色。显然有状态转移方程：<br /><br />dp[i, j] = min{dp[i, k] + dp[i + k, j - k] + sum[i, k] * sum[i + k, j - k]}&nbsp;&amp;nbs...</p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F65435987.html&title=SPOJ+345+Mixtures">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/65435987.html</link>
   <author>shilcare</author>
   <pubDate>Tue, 08 Jun 2010 14:06:41 +0800</pubDate>
  </item>
  <item>
   <title>题目：Sequence</title>
   <description><![CDATA[<p>这是Codeforces上的一道题目。<br /><br />&nbsp;<br /><br /><br /></p><!--sp--><div class="addfav"><br />收藏到：<span class= "delicious"><a href="http://delicious.com/save?url=http%3A%2F%2Fshilcare.blogbus.com%2Flogs%2F64889900.html&title=%E9%A2%98%E7%9B%AE%EF%BC%9ASequence">Del.icio.us</a></span></div><br /><br /><div class="sysmsg"><b><a href="http://www.blogbus.com" target="_blank">博客大巴，你的个人传媒早班车</a></b></div><br /><br />]]></description>
   <link>http://shilcare.blogbus.com/logs/64889900.html</link>
   <author>shilcare</author>
   <pubDate>Wed, 02 Jun 2010 00:21:54 +0800</pubDate>
  </item>
 </channel>
</rss>

